Thursday, August 24, 2006

America's Drunkest Cities

Forbes.com reports on the "drunkeness" rankings of 35 metropolitan areas within the United States. Rankings were based on state laws, number of drinkers, number of heavy drinkers, number of binge drinkers, and the extent of alcoholism.

The top five cities are:

1. Milwaukee
2. Minneapolis-St. Paul
3. Columbus, OH
4. Boston
5. Austin, TX

Hmmm...is this something that Milwaukee can be proud of? (Should Columbus be worried that it is only ranked #3? After all, Columbus has a reputation to uphold now that OSU's football team is the preseason #1 ranked team in country.)

How much weight do you give to such rankings? Take a look at the methodology behind the rankings and suggest an alternative system if you're not satisfied with the approach of Forbes.com.

Thanks to Division of Labour for the tip.

1 comment:

JP Clift said...

The methodology behind this article is a little off. First, reading from the "methodology" link, I noticed that the people at Forbes included "Alcoholism" in determining how drunk a city is. They ranked the cities from the statistics if the number of Alcoholic Anonymous meetings there were in that city. Wouldn't this suggest that that city is LESS drunk? People are trying to end their drinking habits, not the opposite!
Also, wouldn't it be easier in deciding which city is "America's Drunkest City," if one could discover the amount of beer sold per capita? In other words... how many beers is the average person in that city drinking?
The study is misleading because the information, statistics, etc. that were provided, does not relate to the study at all.